-[8z-(12z+3)]=3+(3z+8)

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Solution for -[8z-(12z+3)]=3+(3z+8) equation:


Simplifying
-1[8z + -1(12z + 3)] = 3 + (3z + 8)

Reorder the terms:
-1[8z + -1(3 + 12z)] = 3 + (3z + 8)
-1[8z + (3 * -1 + 12z * -1)] = 3 + (3z + 8)
-1[8z + (-3 + -12z)] = 3 + (3z + 8)

Reorder the terms:
-1[-3 + 8z + -12z] = 3 + (3z + 8)

Combine like terms: 8z + -12z = -4z
-1[-3 + -4z] = 3 + (3z + 8)
[-3 * -1 + -4z * -1] = 3 + (3z + 8)
[3 + 4z] = 3 + (3z + 8)

Reorder the terms:
3 + 4z = 3 + (8 + 3z)

Remove parenthesis around (8 + 3z)
3 + 4z = 3 + 8 + 3z

Combine like terms: 3 + 8 = 11
3 + 4z = 11 + 3z

Solving
3 + 4z = 11 + 3z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-3z' to each side of the equation.
3 + 4z + -3z = 11 + 3z + -3z

Combine like terms: 4z + -3z = 1z
3 + 1z = 11 + 3z + -3z

Combine like terms: 3z + -3z = 0
3 + 1z = 11 + 0
3 + 1z = 11

Add '-3' to each side of the equation.
3 + -3 + 1z = 11 + -3

Combine like terms: 3 + -3 = 0
0 + 1z = 11 + -3
1z = 11 + -3

Combine like terms: 11 + -3 = 8
1z = 8

Divide each side by '1'.
z = 8

Simplifying
z = 8

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